7.A.Father and daughter.B.Waiter and customer.C.Husband and wife.8.A.At11:00.B.At11:10.C.At11:20.9.A.Go skating.B.Play tennisC.Go fishing10.A.It was raining.B.Her bike was broken.C.She got up late.三、语篇理解(每小题1分,共5分)本题你将听到一篇短文。请你根据短文内容和所提出的5个问题,从每小题所给的A、B、C三个选项中,选出一个最佳选项,并在答题卡上将该项涂黑11.What kind of party will be held?A.A house-warming party.B.A birthday party.C.A welcoming party12.What kind of gift shouldn't Lin take?A.The bread.B.The fork.C.The flower.13.What color isn't Lin supposed to wear?A.White.B.Black.C.Yellow.14.What kind of food is popular in Anna's country?A.Sour food.B.Sweet food.C.Sally food.15.What can we learn from this letter?A.We should respect(尊重)different manners.B.We should care about what others think aboutC.We should be relaxed when visiting foreigners.四、听力填空(每小题1分,共5分)本题你将听到一篇短文。请你根据所听内容完成下面表格,并将获取的信息填到答题卡相应的位置上。每空,词。Our townIntroductionOur town has changed a lot in the last 16 years.Jobs*In the past,most people worked as fishermen or 17Now,many people work in 18 factories,offices or banks.*Young people like going to the swimming pool and the 19ActivitiesOlder people like going to the beach and the restaurants.*There are football matches and races in the sports center20 a week.笔试部分(共100分)五、补全对话(每小题1分,共5分)根据对话内容,从方框内所给的选项中选出能填人空白处的最佳选项,并在答题卡上将该项涂黑。选项中有两项为多余项。(Three students are talking on WeChat.)Do you two ever know an invention that can make us travel faster?21九年级英语第2页(共8页)》
65.我们要关注自己身边发生的变化。(focus on)66.一进博物馆,那漂亮的海报就吸引了我的目光。(catch one'seye)67.如果你对这个活动感兴趣,请下周一之前来报名。(sign up)V.阅读表达(共4小题;每小题2分,共8分)阅读下面的短文和问题,根据短文内容,在相应题号后的横线上写下相关信息,完成对该问题的回答。答语要意思清楚,结构正确,书写工整。I had a great interest in researching the topic of how to improve your sense ofdirection,because my own sense of direction is absolutely terrible.Take going to thetoilet in a restaurant,for example.I can find my way there easily enough becausethere are signs pointing me in the right direction.But getting back to my table isanother story.After all,there are no helpful signs saying,"This is where you weresitting less than five minutes ago".However,rather than accept the situation of myself frequently walking intocupboards and backtracking down dead ends,I'm determined to give my sense ofdirection a much-needed improvement.Nowadays,of course,it's easy to rely on GPS(全球卫星定位系统)to find yourway.But if you really want to improve your sense of direction,it's a good idea tocount on yourself.Studying a map and memorizing the way before you set out does have itsbenefits-not least because the amount of mental energy it requires means it's morelikely to stick in your mind.Looking at electronic maps on a big screen-or evenstudying a paper map-also allows you to get a sense of that all-important biggerpicture and how everywhere fits together.Paying full attention is key,too.It's important to notice what's around you-in北京市西城区2022一2023学年度第一学期期末试卷高一英语第14页(共16页)
2023届高三年级5月模拟(五)注意事项:数学·答卷前,考试务必将自已的姓名,准考证号等信息填写在答题卡指定位置上又回答选择题时,法出每个小华案后,用绍笔把答题卡上对应题日的答家标号套黑如署政动:用檬皮擦干净后,再选涂尖他登案标号,回答非选择题时,将答案写在答斑卡上。写在本试卷上无效,一、选择题:本题共8小题,每小题5分,共40分。在每小题给出的四个选项中,只有一项是符合题目要求.1.已知集合4={l,l24,B={x-1≥},则4nCB=A.{-1,2,4B/1,2}C.{-1,2}D.{1}2.已知等腰梯形ABCD满足AB∥CD,AC与BD交于点P,且AB=2CD=2BC,则下列结论错误的是A4C-写而+号西B.而+C.IAP=21PDID.AP=2PC3.已知抛物线M:2=16x的焦点为F,倾斜角为60的直线1过点F交M于A,B两点(A在第一象限),O为坐标原点,过点B作x轴的行线,交直线A0于点D,则点D的横坐标A.-1B.-2c.-4D.-84.某医院安排3名男医生和2名女医生去甲、乙、丙三所医院支援,每所医院安排一到两名医生,其中甲医院要求至少安排一名女医生,则不同的安排方法有A.66种B.54种C.30种D18种5.三棱锥S-ABC中,SA⊥面ABC,AB⊥BC,SA=AB=BC.过点A分别作AE⊥SB,AF⊥SC交SB、SC于点E、F,记三棱锥S-FAE的外接球表面积为S,三棱锥S-ABC的外接球表面积为5,SB.22c5D.36.在面直角坐标系内,已知A(-3,4),B-3,),动点P(x,)满足IPA=2引PB1,则(x-1)2+y-)2(teR)的最小值是A.16B.4.2D.2数学试卷第1页(共4页)
基础题与中考新考法·九年级·全一册·化学课题2化学肥料359考建议用时:10分钟教材改编题B.化肥的过度使用会造成土壤酸化,可用熟石灰改良知识点1化肥的种类及作用272考C.农药施用后,不会通过农作物、农产品等1.(教材P80素材改编)一材多题发生转移化学肥料在农业生产中有着重要作用。现有D.使用农药会导致环境污染,因此要杜绝①硫酸铵[(NH4)2S04]、②硝酸钾(KNO3)、使用③碳酸钾(K,C03)、④磷矿粉[Ca(P04)2]知识点3化肥的简易鉴别52考四种化肥,请结合所学知识回答下列问题。4.(教材P85第2题改编)下列化肥中,从外观1.1(中考新考法·文化典籍一本草纲即可与其他化肥相区别的是(目)《本草纲目》中记载“火药乃焰消、硫黄、A.氯化钾B.硫酸铵杉木炭所合,以为烽燧铳机诸药者”。这里C.磷矿粉D.尿素的“焰消”是一种中药,其主要成分在现代5.(教材P83素材改编)小明同学设计了如图还可作为复合肥料。它是实验对几种化肥进行简易鉴别。A.①B.②硝酸钠C.③D.④硫酸铵实验①硝酸钠1.2欲使冬小麦根系发达,抗寒抗旱,你认氯化铵氯化铵氯化铵实验②为宜施加上述化肥中的(硫酸铵硫酸铵A.①B.②(1)进行实验①时,分别取适量三种化肥C.③D.④加入(填物质名称)混合研磨,观2.(教材P85第5题改编)尿素[C0(NH2)2]是农察现象,即可鉴别出硝酸钠。业生产中使用的化肥之一,不会在土壤中残留(2)进行实验②时,分别取适量两种化肥于有害物质,长期使用没有不良影响。试管中,加入氯化钡溶液,有明显现象的是(1)尿素属于(填“氨”“磷”或(填化学式),发生反应的化学方“钾”)肥。程式为(2)尿素中所含营养元素的质量分数为(保留一位小数,下同)。中考新考法(3)农业生产中若施用12t尿素,可为农作物6.(文化典籍一齐民要术)贾思勰的《齐民要提供t氮元素。术》中记载:“凡美田之法,绿豆为上,小豆知识点2化肥和农药对环境的影响35考胡麻次之。”说明豆科植物与根瘤菌共生起3.(教材P85第2题改编)下列有关化肥和农固氮效果,则使用豆科植物肥田可减少下药的叙述中正确的是列化肥使用量的是(A.化肥对提高农作物的产量具有重要作A.NH,NOB.KCI用,使用越多越好C.K,SOD.Ca(P04)2136
当3x-2=15时,=号(x不是整教,舍去)。故选C二、11.512.713.3314.6015.-116.0提示:16.将x=1代人方程,可得关丁的方科k+=31-2+6.悠理,得2k+h=4-2a.6因为尤论k取何位,该等式都成立,听以b=-2,H.4-2a=0.所以b=-2,a=2.所以a+b=0.故填0三、17.(1)去分丹(两边同乘10),得-4(3y+2)=1-15(y-1).去括号,得-12y-8=1-15y+15.移项,得-12y+15y=1+15+8.合并同类项,得3y=24.系数化为1,得y=8.(2)原方程可化为5(x-4)-号=20(x-3)去分母(两边同乘2),得10(x-4)-5=40(x-3).去括号,得10x-40-5=40x-120移项,得10x-40x=-120+40+5.合并同类项,得-30x=-75.系数化为1,得x=2.5.18.解方程4x=3(x-1)+4(x-3),得x=5.所以a=多所以方程y-5=3a即为y-5=5.解得y=6.19.将2x+3=5x移项,得2-5x=-3.合f同类项,得-3x=-3.系数化为1,得x=1.听以方程4x+2m=3x的解为x=-I.将x=-1代入,4×(-1)+2m=3×(-1)解得m=号20.依题症,列方程为登+号号去分母、去括号,得15x+10=6x+6.移项、合并同类项,得9x=-4.系数化为1,得x=-号21.设该农场去年计划生产玉米x吨,则去年计划生产小麦(200-x)吨.依题意,得(1+5%)x+(1+15%)(200-x)=225.解得x=50.所以200-x=150答:该农场去年计划生产玉米50吨,生产小麦150吨.22.(1)设每套课桌椅的成本为x元.依题意,得60(100-x)=72(100-3-x)解得x=82.答:每套课桌椅的成本为82元(2)72×(100-3-82)=1080(元).答:商店获得的利润为1080元.23.①当3x+1>0时.原方程可化为一元一次方程3x+1=2.它的解是x=子②当3x+1
分数学用报2022一2023学年四川专版(华东师大版)七年级第1~8期MATHEMATICS WEEKLY答案专期所以(+5)(+2)=(+2)0(+5);5.s=t=7.9×102×8.6×10=7.9×8.6×10000000(-3)0(-5)=+8,(-5)0(-3)=+8,=679400000=6.794×10(米).答:卫星绕地球运行一天所经过的路程为代数式的值所以(-3)(-5)=(-5)(-3):(-3)(+4)=-7,(+4)(-3)=-7,6.794×10米.1.B2.B3.15a+b.50所以(-3)(+4)=(+4)本(-3):4.(1)原式=[1-(-6)=7=49:0(+8)=8.(+8)*0=8,有理数的混合运算(2)原式=1P×(-6)+(-6)+6=-6.所以0中(+8)=(+8)00.5.(1)依题意.两人的路程利和等于初始距离,则明所以加法交换律在有理数的(加栗)运算中1.B明和佳佳两人的初始距离为(5a+5)米还适用.2.-32,-9(2)当4=60,b=65时.275×60+5×65=625(米).【第25版】第2章2.9~2.10专题训练3.÷答:两人的初始距离为625米4由定义可知-器×(别】-[位×-2明有理数的乘法法则=-1-×(-)-b×4探索规律有技巧1.D2.01-(景×)例1因为1=1×2-1,5=2×3-1,3原式=-8×名××}=-9子11=3×4-1.4.D19=4×5-1,…,5.因为-5×0=0,(-5)×(-3)=15,(-5)×所以第n个数为n(n+1)-1.所以第7个数是7×(7+1)-1=7×8-0.25=-1.25.0×(-3)=0,0×0.25=0,(-3)×近似数1=56-1=55.0.25=-0.75.故选C.所以最大的积为151.3.1422.2.5671≈2.567.例2因为a2,3a,5a,7a,…3.(1)1411778724≈14.1亿;所以单项式的次数是连续的偶数,系数是有理数的乘法运算律(2)1411778724≈14亿.连续的奇数,即第n个式子为(2-1)a所以第8个式子是(2×8-1)a2×8=15a61.D2.A故填15a6.走进有理数计算巧思园3.(1)原式=25×(-4)×376例3第4个算式:④4×6-52=24-25=-1,=(-100)×376=-37600:第n个算式为n(n+2)-(n+1)2=-1.(2)原式=号×56-号×56+音×56例1原式=(80-6)+(800-5)+(8000-4)+故填4×6-52=24-25=-1:(80000-3)+(800000-2)+(8000000n(n+2)-(n+1)2=-1.=32-63+12=-19.1)=80+800+8000+80000+800000+4.B5.D8000000-(6+5+4+3+2+1)=8888880-21=8888859.【第31版】第3章3.3~3.4专题训练6.乘法交换律,乘法结合律例2网为兮是*是茹+是景可标为整式有理数的除法4+名+878即号}1.C2.A3.104.-91.C2.C4++号++号片所以原武3.(1)原式=0:-++号号6+名+号号8×5子x的分同中含合宁丹,既不是单喷式,也(2)原武=-(3号5)=-(号×)=-号不是多项式,更不是整式4.B5.-62×2022=-8×4×2022=-1011单项式有:-x,10,mn,a;6原武=9×+号×号-号例3若将原式中的各括号内的算式逆序排列后多项式有:x+y,b,6xy+1,22-x-5;原式可写作(得+》-(层+异+)整式有:+,-x,地,10,6y+1,与mm.3++号+-(++++》22-x-5,a.6.D7.-68.2乘除运算有妙招所以2目-4+好》-传+号+*9.6a3-5a2-a+3;-5x3+4xy-3xy2+y210.因为关于x的多项式(a-4)x3-x+x-b的例1原式=0.后+后+君*君+引=-1-2-3-45=-15次数是2,所以a-4=0,b=2.例2原式=-(品×告×3×)=子所以a=4,b=2,所以原式=-15÷2=-7.5.即多项式为-x2+x-2.例3原式=-×=-××4=-8例4将括号内的各个加数都乘以2,可得当x=-2时,-x2+x-2=-(-2)2-2-2=-8.例4原式=×××2+1+号+++分所以1+号++2=2+1+号*++-++整式的加减++别2+1+++分+-11.C2.D3.A=-1×=b4.x-y5.-a+b-c例5原式=-125×0.25×(-8×4×2)×4分=2=2=6.原式=-6a2+2ab-4-5ab+62+4=-3ab.当a=2,b=-1时,(125×8)×(0.25×4)×2×4=1000×1×所以惊式=1-=》原式=-3×2×(-1)=6.7.B2=500.8.2x-y+y2【第29版】第3章3.1~3.2专题训练9.-xy【第27版】第2章2.11~2.15专题训练10.(1)2B-A列代数式=2(2xy-32+4x2)-(3x2+3y2-5y))乘方=4y-62+82-3x2-3y2+5y1.1)2.A=5x2+9xy-9y1.B2.-6.3.-2163.C4.C(2)闪为-a“B与b是同类项,3.-3=-3×3×3=-275.15a6.0所以|x=1,y=2447.04.③5.0,解得x=-1或x=1,y=2.8.10(9-a)+a当x=-1,y=2时,原式=5-18-36=-49:9.ah-)m6当x=1,y=2时,原式=5+18-36=-13.科学记数法10.(1)2x-3看图形找规律(2)t千米;1.12.B3.368000000(3)d本;1.3n+24.16(4)2n-2,2n+22.4n
H代入消元法可消去y解山x,冉将x代入任【第40期】第八章综合测试题意一个方程解出y即可.15.答案不唯一,如:以两个术知数的和构造一个-、1.C2.A3.B4.A5.B6.C方程,即x+y=3,再以两个未知数的差构造7.D8.A9.A10.B11.B12.D出另一个方程,即x一y=1.联立,得提示:x+y=3,x-y=1.1.选项A中第一个方程含有,不是整式方程,16.设小长方形宽为,长为水,依题意,可得方程做不是二元一次方程组:选项B中方程组含有3个未知数,故不是二元一次方程组;选项D中组他210·解科8放一换渗水动y=2x.第二个方程的x,y都是二次的,故不是二元滑地板的面积为30×15=450(方米).次方程组.三、17(1)3x-y=2.①2因为售3是关于y的方程x-刚=1B的9x+8y=17.②方程①变形为y=3x-2.③一个解,所以3+2m=13.解得m=5.将③代人②.得9x+8(3x-2)=17.3.①+②×2,得5x+8x=20+16,即消去了y解得x=1.4.①+②,可以消去y,从而将三元一次方程组转将x=1代人③,得y=1化为二元一次方程组.5.把升代入方程x-y=3,左边=4-1=3.故方程组的解为仁①右边=3,左边=右边,所以选项B符合题意(2)x+y=3,5x-3(x+y)=1.②6.因为3x2m+y2与4xy加-是同类项,所以2a+6=3,①山①+2,得54=5.解得方程组转化为x+y=3,①3m-7=2.②2x-3y=1.②4=1.把4=1代人①,得2+6=3.解得b=1.①×3+②.得5x=10.则a-b=1-1=0.解得x=2.7根据题意,可得+6三4,①山①+②,可将x=2代入方程①,得y=1.{a-b=10.②得2a=6.解得a=3.把a=3代人①,獬得故方程组的解为仔子6=-7所以方程组的解是仔3.所以m18.∫x-y=1-m,①x+2y=1+2m.②(2a+b)=(2×3-7)4=1.①+②,得2x+y=2+m.8饮题电。时得方迎仁解料售将代入方程2x+Y=3,得2+m=3.解得m=1.其代入分外两个方程,得的+如两式相19.(1)根据题意,得2x+4y=-18.加.得7a+7b=7.所以a+b=1.把x=-5代入,得-10+4y=-18.9.因为共换了5斗酒,所以x+y=5.因为一斗清解得y=-2洲价值10斗谷子,一斗醑洲价值3斗谷子,拿30斗谷子换了5斗酒,所以10+3y=30.所以(2)根据题意,得低20所列方程组为位+-0解得仔最10.根据图示和题意,得{±n二8解得m=5,(m-n=2.n=320因为把a否错后得到化:11.根据题意,得x+:+5=8+2+5,解得三0(x+8=2+7.1y=9所以售于是。-山=4的解所以x=1°=1.即5c-d=4.①12.观察待求方程组,不雅发现两个方程都含有式了x+2和y-l.所以设x+2=a,y-1=b,因为正确的解是售则待求方程组变为:3动=8。根据已知所以3m-2=7.②3c+d=4.③条州知此方程组的解为{红=8了即+2=83,山②,得a=3.山①③.可得c=1,d=1.b=1.2.y-1=1.2.所以4cd=3×1X1=3解得/63,y=2.2.21.因为①×2-②能消去x,所以2(m-n)-4=0.即n-n=2二、13.2,2因为②+①能消去y,14.①,②所以-3+32+n=0.即3m+n=3.15.答案不唯一,如+y=3,(x-y=116.450所解保品的-子提示:13.依题意,可得2a-3=1,b-1=1.解得a=2,22.3x+2y=12可化为y=6-3xb=2.因为x,y均为非负整数,14.根据方程组的特点,方程组①,用加减消元法所以x必为偶数.可消去x解出y,再将y代入任意·个方程附当x=0时,y=6;出x即可,故①用加减消元法简单;方程组②,当x=2时,y=3;
8数学用报MATHEMATICS WEEKLY主编:王建超责编:丁明玉崔维娜美编:花玉人教A版高二·2022一2023学年·第1~4期16.解:(1)以A为原点建立空间直角坐标系,如下图第16题图l条件得B(1.0.0),C(1.1.0),D(0.1,0).0.02.20所以E=(分-1,历=0,1,-2)。所以cos(CE.P元)=CE,P西-25CE PD 5因此5与m所成角的余孩值为2.(2)山(1)得CD=(-1,0,0),B7=(-1,0,2)P元=(1.1.-2).因为点F在棱PC上,且PF=APC所以PF=APC=(A,A,-2A),所以BF=Bp+PF=(入-1,A,2-2A)设面CDE的法向量为n=(x,y,z),则:受8得x=0,2x-y+z=0取y=1,则n=(0,1,1).设直线B与面C1)k所成的角为0,则sin9=cos(BF,n)2-λN(A-1)+2+(2-2A22-入N2N6入2-10A+5令t=2-入,则t∈[1,2],所以sin0=20-1w+929-4+6当}号即1=号时,号-14+6有最小值多此时血0取得最人值30A=2-4=马因此当直线BF与面CDE所成的角最大时,A的值为号
答案专期2022一2023学年北师大版高二(A)第31~34期分数学闭报MATHEMATICS WEEKLY10.(1)证明:当b=0,a=1时,f(x)=c-1-sinx,当xe(-3,-2)时f'(x)>0,f(x)单调递增;则'(x)=e-eosx.当x(-2)时f(e)0恒成立,则1+a>0,所以f(x)的极小值点为x=nb.解得a>-1.综上可知,?b≤0时,f(x)无枚值点;b>09.解:(1)根据题意,由于f(x)=x3-3x时∫(x)有一个极小值点,无极大值点所以f'(x)=3x2-3=3(x+1)(x-1)方令f'(x)>0,得到x>1或x0;ix>e时f'(x)0,解得x>:(2)F(x)=g时(x)-a=anE】已知a>0,由(1)可知函数(x)在(0,C)内单令f(x)
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