英语(JJ)答案)
听第6段材料，回答第6、7题。6.When will the woman check out?A.On the 25th.B.On the 26th.C.On the 27th.7.What kind of room does the woman book in the end?A.A single room.B.A double room.C.A twin room.听第7段材料，回答第89题。8.What color shirt does the man like?A.Purple.B.Blue.C.White.9.What size shirt does the man want?A.Small.B.Medium.C.Large.听第8段材料，回答第10至12题。10.What did Sarah do last night?A.She worked overtime.B.She went to the hospital.C.She looked after her mother.11.What was the girl's plan for today?A.Going to the library.B.Doing housework.C.Visiting Maria12.What does the man promise to do?A.Stay at home today B.Lend Sarah his car.C.Help Sarah buy a car.听第9段材料，回答第13至16题。13.What's the relationship between Mark and Tommy?A.Classmates.B.Neighbors.C.Brothers.14.What does Betty want Mark to do?A.Go shopping.B.Help her with French.C.Repair her cell phone.15.What will Mark do this afternoon?A.Make dinner.B.Visit his friendsC.Go to see his doctor.16.What is Tommy's advice for Betty?A.Calling Mark at once.B.Coming to his home.C.Taking the French exam.听第10段材料，回答第17至20题。17.What is Karen's father?A.An engineer.B.A doctor.C.A teacher.18.What is Karen's favorite sport?A.Ping pong.B.Basketball.C.Volleyball.19.What is Karen like?A.Outgoing.B.Caring.C.Careless.20.Where did the speaker spend her summer holidays last year?A.In Chengdu.B.In New York.C.In Amsterdam.高美销试鹭第2出（长10其）
化学试题)
1、启光教育 2023-2024学年度七年级第一学期期末学业质量监测(2024.1)化学答案1、启光教育 2023-2024学年度七年级第一学期期末学业质量监测(2024.1)道德与法治答案2、启光教育 2023-2024学年度七年级第一学期2、启光教育 2023-2024学年度七年级第一学期期末学业质量监测(2024.1)道德与法治试题3、启光教育 2023-2024学年度七年级第一学期期末学业质量监测(2024.1)道德与法治答案
化学答案)
1、启光教育 2023-2024学年度七年级第一学期期末学业质量监测(2024.1)道德与法治答案2、启光教育 2023-2024学年度七年级第一学期期末学业质量监测(2024.1)道德与法治试题
道德与法治试题)
道德与法治答案)
语文试题)
语文答案)
数学试题)
设切点坐标为(11一1+2)则切线的斜k=广(1)=3121·则切线力程为v(1)121(:)·切线过点(12).2-(12)=(31-21)(1-1).化简得1(1一1)=(31一21)(1一1)，1=1或1=0.∴.切线的方程为x一y十1=0或=2.故选AC.12.BD【解题分析】对于选项A.0是函数1()的零点，零点不是一个点，所以选项A错误；对于选项B.令f(.x)=0,则x一0或e一a.r=0.令8)-号，则()=山1，知x()在（一0）上单调递减在(0,1D上单调递减，在(1,十c)上单调递增，g(1)一·如图所示，故选项B正确：对于选项心当。时)-心)=十1)e、当1时e(·/'(.)=(.(+1)e->(.x十1)一1=x≥0，当-1时.令(x)=（.1+1)e.则n'(x)=（.x十2)e,知n(.x)在(-，一2)上单g(x)=调递减.在（一2.一1）上单调递增.(.x)≥m(一2)==u+e-2-≥-1+1>0.所以了'(.x)>0恒成立·无极值点·枚选项C错误；对于选项D./(.x)=(.2+1)e一2.x当x≥-1时.e>.x+1,f(.x)=(x+1)e-2x>(.x+1)2-2.x>0,当-是-2≥-是+2>0e所以(x)是R的增函数故选项)正确.故选B).13.-1【解题分析】/(x)=a.x2十3./({)，则(.x)-2u.x3f(1).令x=1,则(1)=2+3(1)，得-1.14,(2+22【解题分析】已知得对任意x∈0.+)ae-r>2,即a>十2红令g(r)-2,则g(r)=2,可知g(r)在(02)上单调递增，在(2.+o)上单调e递减，·9·【24新·G3ZCJ·数学·参考答案-R一HAIN】
数学答案)
(本小题14分)如图1、图2，在△ABC中，AB=AC=5,BC=8,点M,N分别在AB,BC上，且AM=CN2点P从点M出发沿折线MB-BN匀速移动，到达点N时停止：而点Q在边AC上随点P移动，且始终保持∠APQ=∠A学楼四MB图1B(1)若点P在MB上.图2①求证品怨②当PQ将△ABC的面积分成上下4：5两部分时，求MP的长(2)设点P移动的路程为x①当x=5时，求CQ的长；距当动②当PQ与△ABC的边行时，请直接写出x的取值范围
物理试题)
